JEE Main20265 April 2026Morning ShiftChemistryChemical Bonding and Molecular StructureActual
Consider the following species: BrF₅ , XeF₅^- , BF₄^- , ICl₄^- , XeF₄ , SF₄ , NH₄^+ , ClF₃ , XeF₂ , ICl₂^- Number of species having sp ^3 d hybridized central atom is __________.
Correct answer
0
Step-by-step solution
The steric number H is calculated as H = 1 2 (V + M - C + A) , where V is the number of valence electrons on the central atom, M is the number of monovalent atoms, C is the cationic charge, and A is the anionic charge. For sp^3d hybridization, H = 5 . BrF₅ : H = 1 2 (7 + 5) = 6 ( sp^3d^2 ) XeF₅^- : H = 1 2 (8 + 5 + 1) = 7 ( sp^3d^3 ) BF₄^- : H = 1 2 (3 + 4 + 1) = 4 ( sp^3 ) ICl₄^- : H = 1 2 (7 + 4 + 1) = 6 ( sp^3d^2 ) XeF₄ : H = 1 2 (8 + 4) = 6 ( sp^3d^2 ) SF₄ : H = 1 2 (6 + 4) = 5 ( sp^3d ) NH₄^+ : H = 1 2 (5 + 4