JEE Main20266 April 2026Evening ShiftChemistryChemical Bonding and Molecular StructureActual
Given below are two statements : Statement I : The number of compounds among SO₂ , SO₃ , SF₄ , SF₆ and H₂ S in which sulphur does not obey the Octet rule is 3 . Statement II : Among [ H₂ O, ClF₃ , SF₄ ], [ NH₃ , BrF₅ , SF₄ ], [ BrF₅ , ClF₃ , XeF₄ ] and [ XeF₄ , ClF₃ , H₂ O], the number of sets in which all the molecules have one lone pair of electrons on the central atom is 1 . In the light of the above statements, c
Options
- ABoth Statement I and Statement II are true
- BBoth Statement I and Statement II are false
- CStatement I is true but Statement II is false
- DStatement I is false but Statement II is true
Correct answer
D. Statement I is false but Statement II is true
Step-by-step solution
Statement I: Number of compounds in which sulphur does not follow the octet rule (from SO₂ , SO₃ , SF₄ , SF₆ and H₂S ). SO₂ : The formal-charge-minimised structure O=S=O places 10 electrons around sulphur (expanded octet). SO₃ : With three S=O double bonds, sulphur has 12 electrons around it (expanded octet). SF₄ : 4 bond pairs + 1 lone pair = 10 electrons around S (expanded octet). SF₆ : 6 bond pairs = 12 electrons around S (expanded octet). H₂S : 2 bond pairs + 2 lone pairs = 8 electrons around S (obeys the octet