The sum of the number of lone pairs of electrons on each central atom in the following species is [TeB r _ 6 ] ^ 2 - , [Br F _ 2 ] ^ + , SN F _ 3 and [Xe F _ 3 ] ^ - [Atomic number : N = 7, F = 9, S = 16, Br = 35, Te =

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Correct answer: 6

Number of σ -bonds formed by central metal atom/ ion Number of lone pairs on central metal atom/ ion (i) In [TeB r _ 6 ] ^ 2 - 6 1 (ii) In [Br F _ 2 ] ^ + 2 2 (iii) In SN F _ 3 4 0 (iv) In [Xe F _ 3 ] ^ - 3 3 ⇒ Total number of lone pairs of electrons = 1 + 2 + 0 + 3 = 6

	Number of $\sigma$ -bonds formed by central metal atom/ ion	Number of lone pairs on central metal atom/ ion
(i) ${In \left[TeB{r}_{6}\right]}^{2 -}$	6	1
(ii) $In {\left[Br{F}_{2}\right]}^{+}$	2	2
(iii) $In SN{F}_{3}$	4	0
(iv) $In {\left[Xe{F}_{3}\right]}^{-}$	3	3

The sum of the number of lone pairs of electrons on each central...

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