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JEE Advanced 2014Paper 2
Exam
JEE Advanced
Year
2014
Paper
Paper 2
Subject
Chemistry
Chapter
Chemical Bonding and Molecular Structure

JEE Advanced 2014 · Paper 2 · Chemistry · Chemical Bonding and Molecular Structure

Assuming 2s – 2p mixing is NOT operative, the paramagnetic species...

Assuming 2s–2p2s – 2p mixing is NOT operative, the paramagnetic species among the following is

Options

  1. ABe2B{e}_{2}
  2. BB2{B}_{2}
  3. CC2{C}_{2}
  4. DN2{N}_{2}

Correct answer

C. C2{C}_{2}

Step-by-step solution

Assuming that no 2s-2p mixing takes place
(i) Be2→σ1s2,σ∗1s2,σ2s2,σ∗2s2B{e}_{2} \to \sigma1{s}^{2}, {\sigma}^{*}1{s}^{2}, \sigma2{s}^{2}, {\sigma}^{*}2{s}^{2} (diamagnetic)
(ii) B2→σ1s2,σ∗1s2,σ2s2,σ∗2s2,σ2pz2,{B}_{2} \to \sigma1{s}^{2}, {\sigma}^{*}1{s}^{2}, \sigma2{s}^{2}, {\sigma}^{*}2{s}^{2}, \sigma2{p}_{z}^{2},π2px0π2py0\begin{array}{ll}\pi2{p}_{x}^{0} \\ \pi2{p}_{y}^{0}\end{array}(diamagnetic)<br >(iii) ${C}_{2} \to \sigma1{s}^{2}, {\sigma}^{*}1{s}^{2}, \sigma2{s}^{2}, {\sigma}^{*}2{s}^{2}, \sigma2{p}_{z}^{2},\begin{array}{ll}\pi2{p}_{x}^{1} \\ \pi2{p}_{y}^{1}\end{array},,\begin{array}{ll}{\pi}^{*}2{p}_{x}^{0} \\ {\pi}^{*}2{p}_{y}^{0}\end{array}, {\sigma}^{*}2{p}_{z}^{0}$ (paramagnetic)<br >(iv) ${N}_{2} \to \sigma1{s}^{2}, {\sigma}^{*}1{s}^{2}, \sigma2{s}^{2}, {\sigma}^{*}2{s}^{2}, \sigma2{p}_{z}^{2},\begin{array}{ll}\pi2{p}_{x}^{2} \\ \pi2{p}_{y}^{2}\end{array},,\begin{array}{ll}{\pi}^{*}2{p}_{x}^{0} \\ {\pi}^{*}2{p}_{y}^{0}\end{array}$,σ∗2pz0, {\sigma}^{*}2{p}_{z}^{0} (diamagnetic)
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