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JEE Advanced 2025Paper 1
Exam
JEE Advanced
Year
2025
Paper
Paper 1
Subject
Chemistry
Chapter
Electrochemistry

JEE Advanced 2025 · Paper 1 · Chemistry · Electrochemistry

In an electrochemicalcell, dichromate ions in aqueous acidic medium...

In an electrochemicalcell, dichromate ions in aqueous acidic medium are reduced to Cr3+\mathrm{Cr}^{3+}. The current (in amperes) that flows through the cell for 48.25 minutes to produce 1 mole of Cr3+\mathrm{Cr}^{3+} is _____ . Use: 1 Faraday =96500Cmol−1=96500 \mathrm{C} \mathrm{mol}^{-1}

Correct answer

0

Step-by-step solution

For reduction of dichromate, balanced reaction is : Cr2O7−2(aq)+6e−+14H+(aq)→2Cr3+(aq)+7H2O(l)3Mole1Mole\mathrm{Cr}_2 \mathrm{O}_7^{-2}(\mathrm{aq})+6 \mathrm{e}^{-}+14 \mathrm{H}^{+}(\mathrm{aq}) \rightarrow 2 \mathrm{Cr}^{3+}(\mathrm{aq})+7 \mathrm{H}_2 \mathrm{O}(\mathrm{l}) \qquad \qquad \qquad3 Mole \qquad \qquad \qquad \qquad 1 Mole Number of Farads required =3 mol=3 \mathrm{~mol} Let current =I=\mathrm{I} amperes ⇒I×48.25×6096500=3I=100 A\begin{aligned} & \Rightarrow \frac{I \times 48.25 \times 60}{96500}=3 \\ & I=100 \mathrm{~A} \end{aligned}
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