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An electrochemical cell is fueled by the combustion of butane at 1 bar and 298 K . Its cell potential is X F 10^3 volts, where F is the Faraday constant. The value of X is . Use : Standard Gibbs energies of formation at 298 K are : _f G_ CO ₂ ^ =-394 ~kJ ~mol ⁻¹ ; _f G_ water ^ =-237 ~kJ ~mol ⁻¹ ; _f G_ butane ^ =-18 ~kJ ~mol ⁻¹

Correct answer

0

Step-by-step solution

aligned & C ₄ H ₁₀( ~g )+ 13 2 O ₂( ~g ) 4 CO ₂( ~g )+5 H ₂ O (l) & _ r G ^ =4 _ f G _ CO ₂ ^ +5 _ f G _ H ₂ O ^ - _ f G _ C ₄ H ₁₀ ^ & =4 (-394)+5(-237)+18 & =-2743 ~kJ / mol & _ r G ^ =- nFE ^ & -2743 1000=-26 FE ^ & E ^ = 105.5 ~F 10^3=105.50 aligned

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