JEE Advanced2022ChemistryElectrochemistryActual
Consider the strong electrolytes Z m X n , U m Y p and V m X n . Limiting molar conductivity of U m Y p and V m X n are 250 and 440 S cm 2 mol - 1 , respectively. The value of m + n + p is Given: Ion Z n + U p + V n + X m - Y m - λ 0 S cm 2 mol - 1 50 . 0 25 . 0 100 . 0 80 . 0 100 . 0 λ 0 is the limiting molar conductivity of ions The plot of molar conductivity Λ of Z m X n vs c 1 2 is given below. If
Correct answer
0
Step-by-step solution
λ m = λ m ° - A C For electrolyte Z m X n and from given curve λ m Z m X n = λ m 0 Z m X n - A C - A = 336 - 339 0 . 04 - 0 . 01 = - 3 0 . 03 ⇒ A = 100 ∴ For λ m = 336   S   cm 2   mol - 1 ⇒ 336 = λ m 0 Z m X n - 100 × 0 . 04 λ m 0 = 336 + 4 = 340   S   cm 2   mol - 1 Z m X n ⟶ mZ n + + nX m - ∴    50 m + 80 n = 340 ⇒ 5 m + 8 n = 34