At 298 K , a 1 litre solution containing 10 mmol of Cr 2 O 7 2 - and 100 mmol of Cr 3 + shows a pH of 3 . 0 . Given : Cr 2 O 7 → 2 - Cr 3 + ; E 0 = 1 . 330 V and 2 . 303 RT F = 0 . 059 V The potential for the half cell reaction is x &

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At 298 K , a 1 litre solution containing 10 mmol of Cr 2 O 7 2 - and 100 mmol of Cr 3 + shows a pH of 3 . 0 . Given : Cr 2 O 7 &#8594; 2 - Cr 3 + ; E 0 = 1 . 330 V and 2 . 303 RT F = 0 . 059 V The potential for the half cell reaction is x &#215; 10 - 3 V . The value of x is _____ .

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The balanced half-reaction can be written as follows, Cr 2 O 7 2 - + 14 H + + 6 e - &#8594; 2 Cr 3 + + 7 H 2 O Using Nernst equation E cell = E cell o - 0 . 059 n log products reactants For the above reaction, number of electrons involved n = 6. E = 1 . 33 - 0 . 059 6 log 0 . 1 2 10 - 2 10 - 3 14 E = 1 . 33 - 0 . 059 6 &#215; 42 = 0 . 917 E = 917 &#215; 10 - 3 x = 917 .

At 298 K , a 1 litre solution containing 10 mmol of Cr 2 O 7 2 - and 100 mmol of Cr 3 + shows a pH of 3 . 0 . Given : Cr 2 O 7 → 2 - Cr 3 + ; E 0 = 1 . 330 V and 2 . 303 RT F = 0 . 059 V The potential for the half cell reaction is x × 10 - 3 V . The value of x is _____ .

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At 298 K , a 1 litre solution containing 10 mmol of Cr 2 O 7 2 - and 100 mmol of Cr 3 + shows a pH of 3 . 0 . Given : Cr 2 O 7 &#8594; 2 - Cr 3 + ; E 0 = 1 . 330 V and 2 . 303 RT F = 0 . 059 V The potential for the half cell reaction is x &#215; 10 - 3 V . The value of x is _____ .

Correct answer

Step-by-step solution

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At 298 K , a 1 litre solution containing 10 mmol of Cr 2 O 7 2 - and 100 mmol of Cr 3 + shows a pH of 3 . 0 . Given : Cr 2 O 7 → 2 - Cr 3 + ; E 0 = 1 . 330 V and 2 . 303 RT F = 0 . 059 V The potential for the half cell reaction is x × 10 - 3 V . The value of x is _____ .