Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Advanced 2020Paper 1
Exam
JEE Advanced
Year
2020
Paper
Paper 1
Subject
Chemistry
Chapter
Electrochemistry

JEE Advanced 2020 · Paper 1 · Chemistry · Electrochemistry

Consider a 70 % efficient hydrogen-oxygen fuel cell working under...

Consider a 7070 % efficient hydrogen-oxygen fuel cell working under standard conditions at 11 bar and 298K298K. Its cell reaction is

H2(g)+12O2(g)→H2O(l){H}_{2} ( g ) + \dfrac{1}{2}{O}_{2} ( g ) \to {H}_{2}O ( l )

The work derived from the cell on the consumption of 1.0×10−3mol1 . 0 \times {10}^{- 3}mol of H2(g){H}_{2} ( g ) is used to compress 1.00mol1 . 00mol of a monoatomic ideal gas in a thermally insulated container. What is the change in the temperature (in KK ) of the ideal gas?

The standard reduction potentials for the two half-cells are given below.

O2(g)+4H+(aq)+4e−→2H2O(l),E0=1.23V{O}_{2} ( g ) + 4{H}^{+} ( aq ) + 4{e}^{-} \to 2{H}_{2}O ( l ) , {E}^{0} = 1 . 23V,

2H+(aq)+2e−→H2(g),E0=0.00V2{H}^{+} ( aq ) + 2{e}^{-} \to {H}_{2} ( g ) , {E}^{0} = 0 . 00V

Use F=96500Cmol−1,R=8.314Jmol−1K−1F = 96500C{mol}^{- 1}, R = 8 . 314J{mol}^{- 1}{K}^{- 1}.

Correct answer

13.32

Step-by-step solution

For given reaction H2{H}_{2}\left(g\right) + \dfrac{1}{2}{O}_{2}\left(g\right)\overset{2{e}^{-}}{⟶}{H}_{2}O\left(l\right)E°=1.23VE ° = 1 . 23V

ΔG°=−nFEcell°=[−2×96500×1.23]1×10−3×0.7=−166.173J{\Delta G}^{°} = - {nFE}_{\text{cell}} ° = [ - 2 \times 96500 \times 1 . 23 ] 1 \times {10}^{- 3} \times 0 . 7 = - 166 . 173J

W=166.173JW = 166 . 173J

W=W =nRΔTγ−1\begin{array}{ll}nR \Delta T \\ \gamma - 1\end{array}$</p><p></p><p>166 . 173 = \dfrac{1 \times 8 . 314 \times \Delta T}{\left(\dfrac{5}{3} - 1\right)} = \dfrac{8 . 314 \times 3}{2}\Delta T</p><p></p><p>\Delta T = \dfrac{166 . 173 \times 2}{8 . 314 \times 3} = 13 . 32$

Practice Electrochemistry on Quantrex Academy →

More from Electrochemistry

At 300 K, the molar conductivities of the aqueous solutions of three salts at two… JEE Advanced 2026Given at 298 K: E^ _ Fe^ 2+ /Fe = X Volt; E^ _ Fe^ 3+ /Fe = Y Volt. The E^ _ Fe^ 3+ /Fe^… JEE Main 2026For a general redox reaction Anode : Red_1 arrow Ox_1^ n_1^+ + n_1 e^- Cathode : Ox_2 +… JEE Main 2026Consider the following data. Electrolyte Λ^ ∘ _m (S cm ^2 mol ^ -1 ) BaCl_2 x_1 H_2SO_4… JEE Main 2026One half cell in a voltaic cell is constructed by dipping silver rod in AgNO_3 solution… JEE Main 2026At 298 K , the molar conductivity of x\% (w/w) MX solution (aqueous) is 123.5 S cm^2 mol^… JEE Main 2026An electrochemical cell, consist of the following two redox couples, M^ x+ (aq)/M(s) [E_… JEE Main 2026Consider the following two half-cell reactions along with the standard reduction… JEE Main 2026 Full Electrochemistry list All JEE Advanced PYQs