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JEE Advanced 2025Paper 1
Exam
JEE Advanced
Year
2025
Paper
Paper 1
Subject
Chemistry
Chapter
General Organic Chemistry

JEE Advanced 2025 · Paper 1 · Chemistry · General Organic Chemistry

The monomer (X) involved in the synthesis of Nylon 6,6 gives...

The monomer (X) involved in the synthesis of Nylon 6,6 gives positive carbylamine test. If 10 moles of X\mathbf{X} are analyzed using Dumas method, the amount (in grams) of nitrogen gas evolved is ______ . Use: Atomic mass of N (in amu) = 14The monomer (X) involved in the synthesis of Nylon 6,6 gives positive carbylamine test. If 10 moles of X are analyzed

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Step-by-step solution

The monomer (X) involved in the synthesis of Nylon 6,6 gives positive carbylamine test. If 10 moles of X are analyzed
Hexamethylene diamine series give (+)(+) carbylamine test. CxHyNz+(2x+1/2)CuO→xCO2+y2H2O+z2 N2\mathrm{C}_{\mathrm{x}} \mathrm{H}_{\mathrm{y}} \mathrm{N}_{\mathrm{z}}+(2 \mathrm{x}+1 / 2) \mathrm{CuO} \rightarrow \mathrm{xCO}_2+\frac{\mathrm{y}}{2} \mathrm{H}_2 \mathrm{O}+\frac{\mathrm{z}}{2} \mathrm{~N}_2 (Dumas method) C6H16 N2\mathrm{C}_6 \mathrm{H}_{16} \mathrm{~N}_2 then z2 N2=22 N2=1\frac{\mathrm{z}}{2} \mathrm{~N}_2=\frac{2}{2} \mathrm{~N}_2=1 mole Given 10 mole in this reaction so wN2=10×28=280gm\mathrm{w}_{\mathrm{N}_2}=10 \times 28=280 \mathrm{gm}
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