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JEE Main 20265 AprilEvening Shift
Exam
JEE Main
Year
2026
Date
5 April
Shift
Evening Shift
Subject
Chemistry
Chapter
General Organic Chemistry

JEE Main 2026 · 5 April · Evening Shift · Chemistry · General Organic Chemistry

Identify the correct IUPAC name of hydrocarbon ( x ) containing...

Identify the correct IUPAC name of hydrocarbon (xx) containing three primary carbon atoms and with molar mass 72 g mol−172\text{ g mol}^{-1}.

Options

  1. A1,1-Dimethylcyclopropane
  2. B2,2-Dimethylpropane
  3. C2-Methylbutane
  4. Dn-pentane

Correct answer

C. 2-Methylbutane

Step-by-step solution

Let the hydrocarbon be an alkane with general formula CnH2n+2C_nH_{2n+2}.

Molar mass =14n+2=72⇒14n=70⇒n=5= 14n + 2 = 72 \Rightarrow 14n = 70 \Rightarrow n = 5

The molecular formula is C5H12C_5H_{12}.

The structural isomers of C5H12C_5H_{12} are:

n-pentane: CH3−CH2−CH2−CH2−CH3CH_3-CH_2-CH_2-CH_2-CH_3 (2 primary carbons)

2-methylbutane: CH3−CH(CH3)−CH2−CH3CH_3-CH(CH_3)-CH_2-CH_3 (3 primary carbons)

2,2-dimethylpropane: C(CH3)4C(CH_3)_4 (4 primary carbons)

The hydrocarbon with exactly three primary carbon atoms is 2-methylbutane.

Answer: 2-Methylbutane
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