Consider the following reaction. On estimation of bromine in 1 . 00 g of R using Carius method, the amount of AgBr formed (in g ) is____[Given: Atomic mass of H = 1 , C = 12 , O = 16 , P = 31 , Br = 80 , Ag = 108 ]

Step-by-step solution

2 P + 3 Br 2 → 2 PBr 3 Number of moles in 1 gm of R = 1 250 using Carius method all the Br will be converted into AgBr. So, using POAC method Number of moles of AgBr formed from R = 2 250 Mass of AgBr formed = 2 × 188 250 = 1 . 50 gm