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JEE Advanced 2020Paper 2
Exam
JEE Advanced
Year
2020
Paper
Paper 2
Subject
Chemistry
Chapter
General Organic Chemistry

JEE Advanced 2020 · Paper 2 · Chemistry · General Organic Chemistry

An organic compound ( C _ 8 H _ 10 O _ 2 ) rotates plane-polarized...

An organic compound (C8H10O2)\left({C}_{8}{H}_{10}{O}_{2}\right) rotates plane-polarized light. It produces pink color with neutral FeCl3{FeCl}_{3} solution. What is the total number of all the possible isomers for this compound?An organic compound ( C _ 8 H _ 10 O _ 2 ) rotates plane-polarized light. It produces pink color with neutral FeCl _ 3

Correct answer

6

Step-by-step solution

Since compound C8H10O2{C}_{8}{H}_{10}{O}_{2} corresponds positively to neutral FeCl3{FeCl}_{3} hence it will be a phenolic compound the possible structures which are optically active are as followed

An organic compound ( C _ 8 H _ 10 O _ 2 ) rotates plane-polarized light. It produces pink color with neutral FeCl _ 3

Hence, total optically active isomers will be 66.

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