Amongst the given options, the compound (s) in which all the atoms...

$\text{ In both (b) and (c), all the atoms are present in one single plane }<img src="/api/proxy-image?url=https$ \\ In (a) 1, 3-butadiene, conformational change is possible between $\mathrm{C}_2-\mathrm{C}_3$ bond in which atoms will be present in more than one single plane. In (d) allene, the terminals $\mathrm{H}-\mathrm{C}-\mathrm{H}$ planes are perpendicular to one another. $\text{ Paragraph (12 and 13) The final ozonolysis product indicates that the alkene before }$ Ozonolysis is<img src="/api/proxy-image?url=https%3A%2F%2Ffirebasestorage.googleapis.com%2Fv0%2Fb%2Fquantrexacademy-app.firebasestorage.app%2Fo%2Fquestions%252Ffigs%252Fpyq%252Fjee_advanced%252FPLevuZkZG3_QAMbDUFsU94aLkCRRp7kYv9omXZfxoaA.original.fullsize.png%3Falt%3Dmedia&clean=1&v=wm2" data-qx-orig-src="https://firebasestorage.googleapis.com/v0/b/quantrexacademy-app.firebasestorage.app/o/questions%2Ffigs%2Fpyq%2Fjee_advanced%2FPLevuZkZG3_QAMbDUFsU94aLkCRRp7kYv9omXZfxoaA.original.fullsize.png?alt=media" data-qx-storage-src="https://firebasestorage.googleapis.com/v0/b/quantrexacademy-app.firebasestorage.app/o/questions%2Ffigs%2Fpyq%2Fjee_advanced%2FPLevuZkZG3_QAMbDUFsU94aLkCRRp7kYv9omXZfxoaA.original.fullsize.png?alt=media"> \\ Also \mathrm{P} \left(\mathrm{C}}_{6} \mathrm{H}_{10}\right)has two degree of unsaturation and oxymercuration demercuration hydration indicates that it is an alkyne. As alkyne, on hydration, gives a carbonyl compound which on reduction with \mathrm{NaBH}}_{4}$gives a 2^{{}^{\circ}}$ alcohol.