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JEE Advanced 2024Paper 2
Exam
JEE Advanced
Year
2024
Paper
Paper 2
Subject
Chemistry
Chapter
p Block Elements (Group 15, 16, 17 & 18)

JEE Advanced 2024 · Paper 2 · Chemistry · p Block Elements (Group 15, 16, 17 & 18)

The species formed on fluorination of phosphorus pentachloride in a...

The species formed on fluorination of phosphorus pentachloride in a polar organic solvent are :

Options

  1. A[PF4]+[PF6]−\left[\mathrm{PF}_4\right]^{+}\left[\mathrm{PF}_6\right]^{-}and \left[\mathrm{PCl}_4\right]^{+}[PF6]−\left[\mathrm{PF}_6\right]^{-}
  2. B[PCl4]+[PCl4 F2]−\left[\mathrm{PCl}_4\right]^{+}\left[\mathrm{PCl}_4 \mathrm{~F}_2\right]^{-}and \left[\mathrm{PCl}_4\right]^{+}[PF6]−\left[\mathrm{PF}_6\right]^{-}
  3. CPF3\mathrm{PF}_3 and PCl3\mathrm{PCl}_3
  4. DPF5\mathrm{PF}_5 and PCl3\mathrm{PCl}_3

Correct answer

B. [PCl4]+[PCl4 F2]−\left[\mathrm{PCl}_4\right]^{+}\left[\mathrm{PCl}_4 \mathrm{~F}_2\right]^{-}and \left[\mathrm{PCl}_4\right]^{+}[PF6]−\left[\mathrm{PF}_6\right]^{-}

Step-by-step solution

PCl5\mathrm{PCl}_5 when fluorinated in a polar organic solvent, ionic isomers are formed. [PCl4+][PCl4 F2]−\left[\mathrm{PCl}_4^{+}\right]\left[\mathrm{PCl}_4 \mathrm{~F}_2\right]^{-}(colorless crystals) [PCl4+][PF6]−\left[\mathrm{PCl}_4^{+}\right]\left[\mathrm{PF}_6\right]^{-}(white crystals)
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