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JEE Advanced2015ChemistryRedox ReactionsActual

F e 3 + is reduced to F e 2 + by using

Options

  1. AH 2 O 2 in presence of N a O H
  2. BN a 2 O 2 in water
  3. CH 2 O 2 in presence of H 2 S O 4
  4. DN a 2 O 2 in presence of H 2 S O 4

Correct answer

A. H 2 O 2 in presence of N a O H

Step-by-step solution

In basic medium ( H ₂ O ₂ ) acts as reducing agent. ( Na ₂ O ₂+2 H ₂ O 2 NaOH + H ₂ O ₂ ) (2 Fe ³⁺+ H ₂ O ₂+2 OH - 2 Fe ²⁺+2 H ₂ O + O ₂ )

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