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JEE Advanced 2025Paper 2
Exam
JEE Advanced
Year
2025
Paper
Paper 2
Subject
Chemistry
Chapter
Solid State

JEE Advanced 2025 · Paper 2 · Chemistry · Solid State

The density (in g cm^ -3 ) of the metal which forms a cubic close...

The density (in gcm−3\mathrm{g} \mathrm{cm}^{-3} ) of the metal which forms a cubic close packed (ccp) lattice with an axial distance (edge length) equal to 400 pm is \qquad . Use: Atomic mass of metal =105.6amu=105.6 \mathrm{amu} and Avogadro's constant =6×1023 mol−1=6 \times 10^{23} \mathrm{~mol}^{-1}

Correct answer

11

Step-by-step solution

 CCP : (Z=4,a=400pm,M=105.6g/mol) Density =Z×Ma3×NA=4×105.6(400×10−10)3×6×1023=11.00g/cm3\begin{aligned} & \text{ CCP : } \\ & (\mathrm{Z}=4, \mathrm{a}=400 \mathrm{pm}, \mathrm{M}=105.6 \mathrm{ g} / \mathrm{mol}) \\ & \text{ Density }=\frac{\mathrm{Z} \times \mathrm{M}}{\mathrm{a}^3 \times \mathrm{N}_{\mathrm{A}}} \\ & =\frac{4 \times 105.6}{\left(400 \times 10^{-10}\right)^3 \times 6 \times 10^{23}}=11.00 \mathrm{ g} / \mathrm{cm}^3\end{aligned}
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