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JEE Main 202315 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
15 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Solid State

JEE Main 2023 · 15 April · Morning Shift · Chemistry · Solid State

Which of the following expressions is correct in case of a CsCl...

Which of the following expressions is correct in case of a CsClCsCl unit cell (edge length ‘aa’)??

Options

  1. ArCs++rCl−=a2r{Cs}^{+} + r{Cl}^{-} = \dfrac{a}{2}
  2. BrCs++rCl−=32ar{Cs}^{+} + r{Cl}^{-} = \dfrac{\sqrt{3}}{2}a
  3. CrCs++rCl−=a2r{Cs}^{+} + r{Cl}^{-} = \dfrac{a}{\sqrt{2}}
  4. DrCs++rCl−=ar{Cs}^{+} + r{Cl}^{-} = a

Correct answer

B. rCs++rCl−=32ar{Cs}^{+} + r{Cl}^{-} = \dfrac{\sqrt{3}}{2}a

Step-by-step solution

CsClCsCl has body centered type structure in which Cs+{Cs}^{+} occupies at corner of a cube and Cl–{Cl}^{–} occupies the centre of the cube.

2rCs++2rCl−=3a2r{Cs}^{+} + 2r{Cl}^{-} = \sqrt{3}a (where a is the edge length of the cube)

rCs++rCr=32ar{Cs}^{+} + {r}_{Cr} = \dfrac{\sqrt{3}}{2}a

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