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The boiling point of water in a 0.1 molal silver nitrate solution (solution A ) is x ^ C . To this solution A , an equal volume of 0.1 molal aqueous barium chloride solution is added to make a new solution B. The difference in the boiling points of water in the two solutions A and B is y 10⁻² ^ C . (Assume: Densities of the solutions A and B are the same as that of water and the soluble salts dissociate completely. U

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Step-by-step solution

Given for solution A m = 0 . 1 i= 1 for AgNO 3 = 2 K b = 0 .5   Kg   mol - 1 So ΔT b = T b − T b ∘ = 1   K b m T b − 100 ∘ C = 2 × 0 .5 × 0 .1 T b = 100 ∘ C + 0 .1 = 100 .1 ∘ C

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