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JEE Advanced 2025Paper 1
Exam
JEE Advanced
Year
2025
Paper
Paper 1
Subject
Chemistry
Chapter
States of Matter

JEE Advanced 2025 · Paper 1 · Chemistry · States of Matter

Molar volume (V_m) of a van der Waals gas can be calculated by...

Molar volume (Vm)\left(V_m\right) of a van der Waals gas can be calculated by expressing the van der Waals equation as a cubic equation with VmV_m as the variable. The ratio (in moldm−3\mathrm{mol} \mathrm{dm}^{-3} ) of the coefficient of Vm2V_m^2 to the coefficient of VmV_m for a gas having van der Waals constants a=6.0dm6 atm mol−2andb=0.060dm3 mol−1a=6.0 \mathrm{dm}^6 \mathrm{~atm} \mathrm{~mol}^{-2} and b=0.060 \mathrm{dm}^3 \mathrm{~mol}^{-1} at 300 K and 300 atm is _____ . Use: Universal gas constant (R)=0.082dm3 atm mol−1 K−1(R)=0.082 \mathrm{dm}^3 \mathrm{~atm} \mathrm{~mol}{ }^{-1} \mathrm{~K}^{-1}

Correct answer

0

Step-by-step solution

(P+aVm2)(Vm−b)=RTPVm−bP+aVm−abVm2−RT=0⇒PVm2−(bP+RT)Vm2+aVm−ab=0\begin{aligned} & \left(P+\frac{a}{V_m^2}\right)\left(V_m-b\right)=R T \\ & P V_m-b P+\frac{a}{V_m}-\frac{a b}{V_m^2}-R T=0 \\ & \Rightarrow \quad P V_m^2-(b P+R T) V_m^2+a V_m-a b=0 \end{aligned}CoefficientofCoefficient of\mathrm{V}_{\mathrm{m}}^2=-(\mathrm{bP}+\mathrm{RT})CoefficientofCoefficient of\mathrm{V}_{\mathrm{m}}=\mathrm{a}\text{ Ratio }=-\frac{(\mathrm{bP}+\mathrm{RT})}{\mathrm{a}}=-\left[\frac{0.06 \times 300+24.6}{6}\right]=-7.1 .
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