At the sea level, the dry air mass percentage composition is given...

At the sea level, the dry air mass percentage composition is given as nitrogen gas : 70.0, oxygen gas : 27.0 and argon gas : 3.0. If total pressure is 1.15 atm , then calculate the ratio of followings respectively :
(i) partial pressure of nitrogen gas to partial pressure of oxygen gas
(ii) partial pressure of oxygen gas to partial pressure of argon gas
(Given : Molar mass of

\mathrm{N}, \mathrm{O}

and Ar are 14, 16, and

40 \mathrm{~g} \mathrm{~mol}^{-1}

respectively)

Options

A $4.26,19.3$
B $2.59,11.85$
C $5.46,17.8$
D $2.96,11.2$

Correct answer

D. $2.96,11.2$

Step-by-step solution

\frac{\mathrm{P}_{\mathrm{N}_2}}{\mathrm{Po}_2}=\frac{\mathrm{x}_{\mathrm{N}_2} \cdot \mathrm{P}_{\mathrm{T}}}{\mathrm{x}_{\mathrm{O}_2} \cdot \mathrm{P}_{\mathrm{T}}}=\frac{\mathrm{n}_{\mathrm{N}_2}}{\mathrm{n}_{\mathrm{O}_2}}

{using Dalton's law of partial pressure}

\begin{aligned} & =\frac{70 / 28}{27 / 32}=2.96 \\ & \frac{\mathrm{P}_{\mathrm{O}_2}}{\mathrm{P}_{\mathrm{Ar}}}=\frac{\mathrm{n}_{\mathrm{O}_2}}{\mathrm{n}_{\mathrm{Ar}}}=\frac{27 / 32}{3 / 40}=11.25\end{aligned}

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