At constant temperature, a gas is at a pressure of 940 . 3 mm Hg . The pressure at which its volume decreases by 40 % is ______ mm Hg . (Nearest integer)

Step-by-step solution

From Boyle's Law, P 2 V 2 = P 1 V 1 P 1   = 940 . 3 mm of Hg P 2   = Pressure at which volume is reduced by 40 % V 2   = Volume decreased by 40 %   V 2 = V 1 - 0 . 4   V 1 = 0 . 6   V 1 Then, P 2 = 940 . 3 × V 1 0 . 6 V 1 = 1567 . 16   ≈ 1567   mm   Hg