Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Advanced 2009Paper 1
Exam
JEE Advanced
Year
2009
Paper
Paper 1
Subject
Chemistry
Chapter
States of Matter

JEE Advanced 2009 · Paper 1 · Chemistry · States of Matter

The term that corrects for the attractive forces present in a real...

The term that corrects for the attractive forces present in a real gas in the van der Waals' equation is

Options

  1. Anbn b
  2. Bn2a/V2n^2 a / V^2
  3. C−(n2a/V2)-\left(n^2 a / V^2\right)
  4. D−nb-n b

Correct answer

B. n2a/V2n^2 a / V^2

Step-by-step solution

In the van der Waals' equation (p+n2aV2)(V−nb)=nRT\left(p+\frac{n^2 a}{V^2}\right)(V-n b)=n R T The pressure correction factor \left(n^2 a / V²\right) accounts for intermolecular attraction in real gas.
Practice States of Matter on Quantrex Academy →

More from States of Matter

Two cylinders, both fitted with frictionless pistons, are filled with mixtures of He and… JEE Advanced 2026Molar volume (V_m) of a van der Waals gas can be calculated by expressing the van der… JEE Advanced 2025At the sea level, the dry air mass percentage composition is given as nitrogen gas… JEE Main 2025For a reaction, N_2 O_ 5(~g) arrow 2 NO_ 2(~g) +(1)/(2) O_ 2(~g) in a constant volume… JEE Main 2025A closed vessel contains 10 ~g of an ideal gas X at 300 ~K , which exerts 2 atm pressure.… JEE Advanced 2024A gas has a compressibility factor of 0 . 5 and a molar volume of 0 . 4 dm ^ 3 mol ^ - 1… JEE Advanced 2023A certain quantity of real gas occupies a volume of 0 . 15 dm ^ 3 at 100atm and 500K when… JEE Main 2023At 600K , the root mean square ( rms ) speed of gas X (molar mass = 40 ) is equal to the… JEE Main 2023 Full States of Matter list All JEE Advanced PYQs