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JEE Advanced 2024Paper 1
Exam
JEE Advanced
Year
2024
Paper
Paper 1
Subject
Chemistry
Chapter
Thermodynamics (C)

JEE Advanced 2024 · Paper 1 · Chemistry · Thermodynamics (C)

Consider the following volume-temperature (V-T) diagram for the...

Consider the following volume-temperature (V−T)(\mathrm{V}-\mathrm{T}) diagram for the expansion of 5 moles of an ideal monoatomic gas. Consider the following volume-temperature (V-T) diagram for the expansion of 5 moles of an ideal monoatomic gas. Considering only P-V work is involved, the total change in enthalpy (in Joule) for the transformation of state in the sequence X→Y→Z\mathbf{X} \rightarrow \mathbf{Y} \rightarrow \mathbf{Z} is ________. [Use the given data: Molar heat capacity of the gas for the given temperature range, CV,m=12 J K−1mol−1\mathrm{C}_{\mathrm{V}, \mathrm{m}}=12 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{mol}^{-1} and gas constant, R=8.3 J K−1 mol−1]\left.\mathrm{R}=8.3 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right]

Correct answer

0

Step-by-step solution

For ideal gas Δ\Delta\mathrm{H}=\mathrm{nC}PΔT_{\mathrm{P}} \Delta \mathrm{T} ∵CP=CV+R=12+8.3=20.3 J/K\because \quad \mathrm{C}_{\mathrm{P}}=\mathrm{C}_{\mathrm{V}}+\mathrm{R}=12+8.3=20.3 \mathrm{~J} / \mathrm{K}-mole ∴ΔH=5×20.3×(415−335)\therefore \Delta H=5 \times 20.3 \times(415-335) ΔH=8120\Delta H=8120 Joule
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