A reversible cyclic process for an ideal gas is shown below. Here, $P, V, andT$ are pressure, volume and temperature, respectively. The thermodynamic parameters $q, w, HandU$ are heat, work, enthalpy and internal energy, respectively.

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Correct answer: B. w _ BC = P _ 2 ( V _ 2 - V _ 1 )and q _ BC = ∆ H _ AC

AC → Isochoric AB → Isothermal BC → Isobaric # q _ AC = ∆ U _ BC = n C _ V ( T _ 2 - T _ 1 ) W _ AB = nR T _ 1 ln ( V _ 2 V _ 1 ) A (wrong) # q _ BC = ∆ H _ AC = n C _ P ( T _ 2 - T _ 1 ) W _ BC = - P _ 2 ( V _ 1 - V _ 2 ) B (correct) # n C _ P ( T _ 1 - T _ 2 ) ∆ H _ CA # D (wrong)

A reversible cyclic process for an ideal gas is shown below. Here,...

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