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JEE Advanced 2023Paper 2
Exam
JEE Advanced
Year
2023
Paper
Paper 2
Subject
Mathematics
Chapter
Complex Number

JEE Advanced 2023 · Paper 2 · Mathematics · Complex Number

Let A _ 1 , A _ 2 , A _ 3 , , A _ 8 be the vertices of a regular...

Let A1,A2,A3,…,A8{A}_{1}, {A}_{2}, {A}_{3}, \ldots , {A}_{8} be the vertices of a regular octagon that lie on a circle of radius 22. Let PP be a point on the circle and let PAiP{A}_{i} denote the distance between the points PP and Ai{A}_{i} for i=1,2,…,8i = 1, 2, \ldots , 8. If PP varies over the circle, then the maximum value of the product PA1⋅PA2…⋅PA8P{A}_{1} \cdot P{A}_{2} \ldots \cdot P{A}_{8}, is

Correct answer

512

Step-by-step solution

Given,

A1,A2,A3,…,A8{A}_{1}, {A}_{2}, {A}_{3}, \ldots , {A}_{8} vertices of a regular octagon lying on a circle of radius 22.

Now using the concept of nth{n}^{th} root of unity,

Let any point PP be, Z=(2)(1)1/8Z = ( 2 ) ( 1{)}^{1 / 8}

⇒Z8=28×1⇒ {Z}^{8} = {2}^{8} \times 1

⇒Z8−28=0⇒ {Z}^{8} - {2}^{8} = 0

⇒Z=2,2α,2α2,2α3,…,2α7;{hereα=ei2π8}⇒ Z = 2, 2\alpha, 2{\alpha}^{2}, 2{\alpha}^{3}, \ldots , 2{\alpha}^{7}; \left\{\text{here}\alpha = {e}^{i\dfrac{2\pi}{8}}\right\}

⇒Z8−28=(Z−2)(Z−2α)(Z−2α2)(Z−2α3)…(Z−2α7)⇒ {Z}^{8} - {2}^{8} = ( Z - 2 ) ( Z - 2\alpha ) \left(Z - 2{\alpha}^{2}\right)\left(Z - 2{\alpha}^{3}\right) \ldots \left(Z - 2{\alpha}^{7}\right)

⇒∣Z8−28∣=∣Z−2∣∣Z−2α∣….∣Z−2α7∣⇒ \left|{Z}^{8} - {2}^{8}\right| = | Z - 2 | | Z - 2\alpha | \ldots . \left|Z - 2{\alpha}^{7}\right|

But∣Z8+(−28)∣≤∣Z∣8+28\text{But}\left|{Z}^{8} + \left(- {2}^{8}\right)\right| \le | Z{|}^{8} + {2}^{8}

⇒∣Z−2∣∣Z−2α∣…∣Z−2α7∣≤∣Z∣8+28≤28+28≤29\begin{array}{ll}⇒ | Z - 2 | | Z - 2\alpha | \ldots \left|Z - 2{\alpha}^{7}\right|\le | Z{|}^{8} + {2}^{8} \\ \le {2}^{8} + {2}^{8} \\ \le {2}^{9}\end{array}

⇒Max(PA1⋅PA2….PA8)=29=512⇒ Max \left(P{A}_{1} ⋅ P{A}_{2} \ldots . P{A}_{8}\right) = {2}^{9} = 512

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