If the angles A, B and C of a triangle are in an arithmetic progression and if a, b and c denote the lengths of the sides opposite to A, B and C respectively, then the value of the expression a c 2 C+ c a 2 A is

Step-by-step solution

Since, A, B, C are in AP aligned & 2 B=A+C ie, B=60^ & a c (2 C C)+ c a (2 A A) & =2 k(a C+c A) & [ array l using, a A = b B = c C = 1 k array ] & =2 k(b) & =2 B aligned = 3 [using, b=a C+c A]