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JEE Advanced 2018Paper 1
Exam
JEE Advanced
Year
2018
Paper
Paper 1
Subject
Physics
Chapter
Capacitance

JEE Advanced 2018 · Paper 1 · Physics · Capacitance

Three identical capacitors C _ 1 , C _ 2 and C _ 3 have a...

Three identical capacitors C1,C2andC3{C}_{1}, {C}_{2}and{C}_{3} have a capacitance of 1.0\muF1.0\muF each and they are uncharged initially. They are connected in a circuit as shown in the figure and C1{C}_{1} is then filled completely with a dielectric material of relative permittivity ϵr{ϵ}_{r} . The cell electromotive force (emf) V0=8V{V}_{0} = 8V . First the switch S1{S}_{1} is closed while the switch S2{S}_{2} is kept open. When the capacitor C3{C}_{3} is fully charged, S1{S}_{1} is opened and S2{S}_{2} is closed simultaneously. When all the capacitors reach equilibrium, the charge on C3{C}_{3} is found to be 5\muC5\muC . The value of ϵr{ϵ}_{r} =____________.
Three identical capacitors C _ 1 , C _ 2 and C _ 3 have a capacitance of 1.0 each and they are uncharged initially.

Correct answer

0

Step-by-step solution

Three identical capacitors C _ 1 , C _ 2 and C _ 3 have a capacitance of 1.0 each and they are uncharged initially. Three identical capacitors C _ 1 , C _ 2 and C _ 3 have a capacitance of 1.0 each and they are uncharged initially. Applying loop rule 51−3∈r−31=0\dfrac{5}{1} - \dfrac{3}{{\in}_{r}} - \dfrac{3}{1} = 0 3∈r=2\dfrac{3}{{\in}_{r}} = 2 ∈r=1.50{\in}_{r} = 1.50
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