JEE Advanced2016PhysicsExperimental PhysicsActual
There are two vernier calipers both of which have 1 cm divided into 10 equal divisions on the main scale. The Vernier scale of one of the calipers C 1 has 10 equal divisions that correspond to 9 main scale divisions. The Vernier scale of the other caliper C 2 has 10 equal divisions that correspond to 11 main scale divisions. The readings of the two calipers are shown in the figure. The measured values (in cm ) by cal
Options
- A2 . 87 and 2 . 86
- B2 . 87 and 2 . 82
- C2 . 87 and 2 . 83
- D2 . 85 and 2 . 82
Correct answer
C. 2 . 87 and 2 . 83
Step-by-step solution
For caliper C 1 10   VSD = 9   MSD LC = 1   MSD - 1   VSD LC = 0 . 01   cm Measured value = Main scale reading + vernier scale reading × least count = 2 .8 + 7 × 0 .01   cm = 2 . 87   cm For caliper C 2 10   VSD = 11   MSD LC = - 0 . 01   cm (Negative least count means we have to take VSR from the right of the scale 10 ‐ 7 ) Measured value = 2 .8 + 10 - 7 × 0 .01   cm = 2 . 83   cm