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One mole of a monatomic ideal gas undergoes the cyclic process J K L M J , as shown in the P-T diagram. Match the quantities mentioned in List-I with their values in List-II and choose the correct option. [ R is the gas constant.] ( array l|l List-I & List-II (P) Work done in the complete cyclic process & (1) R T₀-4 R T₀ 2 (Q) Change in the internal energy of the gas in the process JK & (2) 0 (R) Heat given to the ga

Options

  1. AP 1 ; Q 3 ; R 5 ; S 4
  2. BP 4 ; Q 3 ; R 5 ; S 2
  3. CP 4 ; Q 1 ; R 2 ; S 2
  4. DP 2 ; Q 5 ; R 3 ; S 4

Correct answer

B. P 4 ; Q 3 ; R 5 ; S 2

Step-by-step solution

aligned & J ( P ₀, ~V ₀, ~T ₀ ) & K ( P ₀, 3 ~V ₀, 3 ~T ₀ ) & M (2 P ₀, V ₀ 2 , ~T ₀ ) & L (2 P ₀, 3 ~V ₀ 2 , 3 ~T ₀ ) & P ₀ ~V ₀= nRT ₀ & JK isobaric W = P ₀ (2 ~V ₀ )=2 nRT ₀ & U = 3 2 nR (2 ~T ₀ )=3 nRT ₀ & KL isothermal W = nR (3 ~T ) ( 1 2 )=-3 nRT ₀ n 2 & U =0 Q =-3 nRT ₀ 2 & LM isobaric =2 P ₀ (- V ₀ )=-2 nRT e ₀ & MJ isothermal nRT n ₀ 2 ; U =0 & WD net =-2 nRT e ₀ 2 & P 4, Q 3, R 5, ~S 2 aligned

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