JEE Main20249 Apr 2024Evening ShiftPhysicsThermodynamicsActual
A real gas within a closed chamber at 27^ C undergoes the cyclic process as shown in figure. The gas obeys P V^3=R T equation for the path A to B . The net work done in the complete cycle is (assuming R=8 ~J / mol K ):
Options
- A20 ~J
- B205 ~J
- C-20 ~J
- D225 ~J
Correct answer
B. 205 ~J
Step-by-step solution
W _ AB = PdV (Assuming T to be constant) aligned & = RTdV V ^3 & = RT ₂^4 ~V ⁻³ dV & =8 300 (- 1 2 [ 1 4^2 - 1 2^2 ] ) & =225 ~J aligned aligned & W _ BC = P ₄^2 dV =10(2-4)=-20 ~J & ~W _ CA =0 & W _ cycle =205 ~J aligned