One mole of a monatomic ideal gas undergoes four thermodynamic processes as shown schematically in the PV - diagram below. Among these four processes, one is isobaric, one is isochoric, one is isothermal and one is adiabatic. Match the processes mentioned in List-1 with the corresponding statements in List-II. List-I List-II A) In process I P) Work done by the gas is zero B) In process I I Q) Temperature of the gas r

Step-by-step solution

Process - I is an adiabatic process ∆ Q = ∆ U + W ∆ Q = 0 W = - ∆ U Volume of gas is decreasing ⇒ W < 0 ∆ U > 0 ⇒ Temperatuer of gas increases ⇒ No heat is exchanged between the gas and surrounding. Process - I I is an isobaric process (Pressure remain constant) W = P ∆ V = 3 P 0 3 V 0 - V 0 = 6 P 0 V 0 Process - I I I is an isochoric process (Volume remain constant) ∆ Q = ∆ U + W W = 0 ∆ Q = ∆ U Process - I V is an isothermal process (Temperature remains constant) ∆ Q = ∆ U + W ∆ U = 0