One mole of an ideal monatomic gas undergoes an adiabatic expansion in which its volume becomes eight times its initial value. If the initial temperature of the gas is 100K and the universal gas constant R = 8.0Jmo l ^

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Correct answer: 900

V _ i = V V _ f = 8V For adiabatic process γ = 5/3 for monoatomic gas T _ 1 ⋅ V _ 1 ^ γ - 1 = T _ 2 ⋅ V _ 2 ^ γ - 1 100(V)(2)/(3) = T _ 2 (8V)(2)/(3) T _ 2 = 25K Loss in internal energy ∆ U = n C _ v ∆ T = 1((fR)/(2))[100 - 25] = 12 × 75 = 900J

One mole of an ideal monatomic gas undergoes an adiabatic expansion...

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