JEE Main 20268 AprilEvening Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 8 April
- Shift
- Evening Shift
- Subject
- Chemistry
- Chapter
- Alcohols Phenols and Ethers
JEE Main 2026 · 8 April · Evening Shift · Chemistry · Alcohols Phenols and Ethers
The major product of which of the following reaction is not...
The major product of which of the following reaction is not obtained by rearrangement reaction?








Options
- A

- B

- C

- D

Correct answer
B. 
Step-by-step solution
In option (A), the Friedel-Crafts alkylation of benzene with 1-chloropropane involves the formation of a primary carbocation, . This undergoes a 1,2-hydride shift to form a more stable secondary carbocation, , which then attacks the benzene ring to yield cumene. Thus, rearrangement occurs.
In option (B), the acid-catalyzed dehydration of tert-butyl alcohol proceeds via the formation of a tert-butyl carbocation, . Since it is already a highly stable tertiary carbocation, it does not undergo any rearrangement and directly loses a proton to form 2-methylpropene.
In option (C), the isomerization of n-hexane in the presence of anhydrous and proceeds via the formation of carbocations that undergo skeletal rearrangements to form more stable branched isomers like 2-methylpentane.
In option (D), the acid-catalyzed dehydration of neopentyl alcohol initially forms a primary neopentyl carbocation, . This undergoes a 1,2-methyl shift to form a more stable tertiary carbocation, , which then loses a proton to yield 2-methyl-2-butene. Thus, rearrangement occurs.
Therefore, the reaction in option (B) is the only one where the major product is not obtained by a rearrangement reaction.
Answer:
In option (B), the acid-catalyzed dehydration of tert-butyl alcohol proceeds via the formation of a tert-butyl carbocation, . Since it is already a highly stable tertiary carbocation, it does not undergo any rearrangement and directly loses a proton to form 2-methylpropene.
In option (C), the isomerization of n-hexane in the presence of anhydrous and proceeds via the formation of carbocations that undergo skeletal rearrangements to form more stable branched isomers like 2-methylpentane.
In option (D), the acid-catalyzed dehydration of neopentyl alcohol initially forms a primary neopentyl carbocation, . This undergoes a 1,2-methyl shift to form a more stable tertiary carbocation, , which then loses a proton to yield 2-methyl-2-butene. Thus, rearrangement occurs.
Therefore, the reaction in option (B) is the only one where the major product is not obtained by a rearrangement reaction.
Answer: