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JEE Main 20266 AprilMorning Shift
Exam
JEE Main
Year
2026
Date
6 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Alcohols Phenols and Ethers

JEE Main 2026 · 6 April · Morning Shift · Chemistry · Alcohols Phenols and Ethers

4.7 g of phenol is heated with Zn to give product X. If this...

4.74.7 g of phenol is heated with Zn to give product X. If this reaction goes to 60%60\% completion then the number of moles of compound X formed will be _______ ×10−2\times 10^{-2}. (Nearest Integer) (Given molar mass in g mol−1^{-1}: H:1, C:12, O:16)

Correct answer

0

Step-by-step solution

The chemical reaction of phenol with zinc dust is given by:

C6H5OH+Zn→ΔC6H6+ZnOC_6H_5OH + Zn \xrightarrow{\Delta} C_6H_6 + ZnO

Product X is benzene (C6H6C_6H_6).

Molar mass of phenol (C6H5OHC_6H_5OH) = 6×12+6×1+16=946 \times 12 + 6 \times 1 + 16 = 94 g mol−1^{-1}

Number of moles of phenol taken = 4.794=0.05\dfrac{4.7}{94} = 0.05 mol

From the stoichiometry of the reaction, 1 mole of phenol produces 1 mole of benzene.

Theoretical moles of X formed = 0.050.05 mol

Since the reaction goes to 60%60\% completion, the actual moles of X formed is:

0.05×60100=0.030.05 \times \dfrac{60}{100} = 0.03 mol

This can be written as 3×10−23 \times 10^{-2} mol.

Answer: 33
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