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JEE Main 201912 JanuaryMorning Shift

Exam: JEE Main
Year: 2019
Date: 12 January
Shift: Morning Shift
Subject: Chemistry
Chapter: Aldehydes and Ketones

JEE Main 2019 · 12 January · Morning Shift · Chemistry · Aldehydes and Ketones

In the following reaction Aldehyde + Alcohol HCl → Acetal Aldehyde...

In the following reaction
Aldehyde + Alcohol\overset{HCl}{\to}Acetal

<table border="1" cellpadding="1" cellspacing="1" style="width:500px;"> <tbody> <tr> <td style="text-align: center;">

Aldehyde

</td> <td style="text-align: center;">

Alcohol

</td> </tr> <tr> <td style="text-align: center;">

HCHO

</td> <td style="text-align: center;">

t - BuOH

</td> </tr> <tr> <td style="text-align: center;">

{CH}_{3}CHO

</td> <td style="text-align: center;">

MeOH$ The best combination is: In the following reaction Aldehyde + Alcohol HCl → Acetal Aldehyde Alcohol HCHO t - BuOH CH _ 3 CHO MeOH The best

In the following reaction Aldehyde + Alcohol HCl → Acetal Aldehyde Alcohol HCHO t - BuOH CH _ 3 CHO MeOH The best

Options

A $HCHO$ and $MeOH$
B ${CH}_{3}CHO$ and $t - BuOH$
C ${CH}_{3}CHO$ and $MeOH$
D $HCHO$ and $\text{t-}BuOH$

Correct answer

A. $HCHO$ and $MeOH$

Step-by-step solution

Formation of an acetal occurs when the hydroxyl group of a hemiacetal becomes protonated and is lost as water. The carbocation that is produced is then rapidly attacked by a molecule of alcohol. Loss of the proton from the attached alcohol gives the acetal.

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