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JEE Main 20265 AprilMorning Shift
Exam
JEE Main
Year
2026
Date
5 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Biomolecules

JEE Main 2026 · 5 April · Morning Shift · Chemistry · Biomolecules

Identify the correct statements. A. Glucose exists in two anomeric...

Identify the correct statements.
A. Glucose exists in two anomeric forms.
B. Anomers of glucose differ in configuration at C−1-1 in cyclic hemiacetal structure.
C. Melting point of α\alpha-anomer of glucose is greater than β\beta-anomer.
D. Specific rotation of α\alpha-anomer is +19°+19° while for β\beta-anomer is +112°+112°
E. α\alpha and β\beta-anomers of glucose are prepared by crystallization of saturated glucose solution at 303303 K and 371371 K respectively.
Choose the correct answer from the options given below:

Options

  1. AA and B Only
  2. BB and C Only
  3. CA, B and D Only
  4. DA, B and E Only

Correct answer

D. A, B and E Only

Step-by-step solution

Statement A is correct because glucose exists in two anomeric forms, α\alpha-D-glucose and β\beta-D-glucose.

Statement B is correct because the two anomers differ only in the configuration of the hydroxyl group at C−1-1, which is the anomeric carbon in the cyclic hemiacetal structure.

Statement C is incorrect because the melting point of the α\alpha-anomer is 419419 K, which is less than the melting point of the β\beta-anomer (423423 K).

Statement D is incorrect because the specific rotation of the α\alpha-anomer is +112∘+112^{\circ} and that of the β\beta-anomer is +19∘+19^{\circ}.

Statement E is correct because the α\alpha-form is obtained by crystallization from a concentrated solution of glucose at 303303 K, while the β\beta-form is obtained by crystallization from a hot and saturated aqueous solution at 371371 K.

Thus, statements A, B, and E are correct.

Answer: A, B and E Only
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