JEE Main 202622 JanuaryEvening Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 22 January
- Shift
- Evening Shift
- Subject
- Chemistry
- Chapter
- Biomolecules
JEE Main 2026 · 22 January · Evening Shift · Chemistry · Biomolecules
Match List - I with List - II. List - I List - II Reaction of...
Match List - I with List - II.
Choose the correct answer from the options given below :
| List - I | List - II |
| Reaction of Glucose with | Product formed |
| A. Hydroxylamine | I. Gluconic acid |
| B. Br_{2} water | II. Glucose pentacetate |
| C. Excess acetic anhydride | III. Saccharic acid |
| D. Concentrated HNO_{3} | IV. Glucoxime |
Choose the correct answer from the options given below :
Options
- AA-III, B-I, C-IV, D-II
- BA-I, B-III, C-IV, D-II
- CA-IV, B-III, C-II, D-I
- DA-IV, B-I, C-II, D-III
Correct answer
D. A-IV, B-I, C-II, D-III
Step-by-step solution
Glucose reactions: A + Hydroxylamine forms glucoxime (IV) via condensation with aldehyde group.
B + Br₂ water oxidizes aldehyde to carboxylic acid, forming gluconic acid (I).
C + Excess acetic anhydride acetylates all hydroxyl groups to form glucose pentaacetate (II).
D + Concentrated HNO₃ oxidizes both aldehyde and primary alcohol groups to form saccharic acid (III).
The correct matching is A-IV, B-I, C-II, D-III.
B + Br₂ water oxidizes aldehyde to carboxylic acid, forming gluconic acid (I).
C + Excess acetic anhydride acetylates all hydroxyl groups to form glucose pentaacetate (II).
D + Concentrated HNO₃ oxidizes both aldehyde and primary alcohol groups to form saccharic acid (III).
The correct matching is A-IV, B-I, C-II, D-III.