- Exam
- JEE Main
- Year
- 2022
- Date
- 27 July
- Shift
- Morning Shift
- Subject
- Chemistry
- Chapter
- Biomolecules
JEE Main 2022 · 27 July · Morning Shift · Chemistry · Biomolecules
A sugar ' X ' dehydrates very slowly under acidic condition to give...
Options
- AAldopentose
- BAldotetrose
- COxalic acid
- DKetotetrose
Correct answer
A. Aldopentose
Step-by-step solution
Seliwanoff’s test is a chemical test which distinguishes between aldose and ketose sugars. If the sugar contains a ketone group, it is a ketose. If a sugar contains an aldehyde group, it is an aldose. This test relies on the principle that, when heated, ketoses are more rapidly dehydrated than aldoses. It is named after Theodor Seliwanoff, the chemist that devised the test. When added to a solution containing ketoses, a red color is formed rapidly indicating a positive test. When added to a solution containing aldoses, a slower forming light pink is observed instead. The acidic dehydration of the different aldopentoses gives furfural. This furfural combines with resorcinol to give cherry red product.