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JEE Main 202431 JanuaryEvening Shift
Exam
JEE Main
Year
2024
Date
31 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Carboxylic Acid Derivatives

JEE Main 2024 · 31 January · Evening Shift · Chemistry · Carboxylic Acid Derivatives

The azo-dye (Y) formed in the following reactions is Sulphanilic...

The azo-dye (Y)\left(Y\right) formed in the following reactions is Sulphanilic acid +NaNO2+CH3COOH→X+ {NaNO}_{2} + {CH}_{3}COOH \to X

The azo-dye (Y) formed in the following reactions is Sulphanilic acid + NaNO _ 2 + CH _ 3 COOH → X

Options

  1. ALet L_1 be the line of intersection of the planes given by the equation- 2 x+3 y+z=4 and x+2 y+z=5 . Let L_2 be the
  2. BLet L_1 be the line of intersection of the planes given by the equation- 2 x+3 y+z=4 and x+2 y+z=5 . Let L_2 be the
  3. CLet L_1 be the line of intersection of the planes given by the equation- 2 x+3 y+z=4 and x+2 y+z=5 . Let L_2 be the
  4. DLet L_1 be the line of intersection of the planes given by the equation- 2 x+3 y+z=4 and x+2 y+z=5 . Let L_2 be the

Correct answer

D. Let L_1 be the line of intersection of the planes given by the equation- 2 x+3 y+z=4 and x+2 y+z=5 . Let L_2 be the

Step-by-step solution

Reaction of aniline sulphonic acid with NaNO2+CH3COOH{NaNO}_{2} + {CH}_{3}COOH gives diazo ester sulphonic acid. Which on further treatment with naphthalene derivative undergoes diazo coupling reaction to give red azo dye.

The azo-dye (Y) formed in the following reactions is Sulphanilic acid + NaNO _ 2 + CH _ 3 COOH → X

The azo-dye (Y) formed in the following reactions is Sulphanilic acid + NaNO _ 2 + CH _ 3 COOH → X

This is known as Griess-Ilosvay test. 

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