JEE Main202126 Aug 2021Evening ShiftChemistryCarboxylic Acid DerivativesActual
Match List - I with List - II. List - I (Chemical Reaction) List - II (Reagent used) a CH 3 COOCH 2 CH 3 → CH 3 CH 2 OH i CH 3 MgBr / H 3 O + (one equivalent) b CH 3 COOCH 3 → CH 3 CHO ii H 2 SO 4 / H 2 O c CH 3 C ≡ N → CH 3 CHO iii DIBAL - H / H 2 O d iv SnCl 2 , HCl / H 2 O Choose the most appropriate match.
Options
- A( a ) - ( ii ) ,   ( b ) - ( iii ) ,   ( c ) - ( iv ) ,   ( d ) - ( i )
- B( a ) - ( ii ) ,   ( b ) - ( iv ) ,   ( c ) - ( iii ) ,   ( d ) - ( i )
- C( a ) - ( iii ) ,   ( b ) - ( ii ) ,   ( c ) - ( i ) ,   ( d ) - ( iv )
- D( a ) - ( iv ) ,   ( b ) - ( ii ) ,   ( c ) - ( iii ) ,   ( d ) - ( i )
Correct answer
A. ( a ) - ( ii ) ,   ( b ) - ( iii ) ,   ( c ) - ( iv ) ,   ( d ) - ( i )
Step-by-step solution
(a) CH 3 COOCH 2 CH 3 ⟶ H 2 SO 4 / H 2 O CH 3 CH 2 OH (Hydrolysis of ester) (b) CH 3 COOCH 3 ⟶ DIBAL - H CH 3 CHO (Reduction of ester) (c) CH 3 ≡ N ⟶ SnCl 2 , HCl / H 2 O CH 3 CHO (Reduction followed by hydrolysis) (d) (Nucleophillic addition reaction)