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JEE Main 20199 AprilMorning Shift
Exam
JEE Main
Year
2019
Date
9 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Carboxylic Acid Derivatives

JEE Main 2019 · 9 April · Morning Shift · Chemistry · Carboxylic Acid Derivatives

The major product of the following reaction is: C H _ 3 CH = CHC O...

The major product of the following reaction is:
CH3CH=CHCO2CH3→LiAlH4C{H}_{3}CH = CHC{O}_{2}C{H}_{3}\overset{LiAl{H}_{4}}{\to}The major product of the following reaction is: C H _ 3 CH = CHC O _ 2 C H _ 3 LiAl H _ 4 →

Options

  1. ACH3CH2CH2CO2CH3C{H}_{3}C{H}_{2}C{H}_{2}C{O}_{2}C{H}_{3}
  2. BCH3CH=CHCH2OHC{H}_{3}CH = CHC{H}_{2}OH
  3. CCH3CH2CH2CH2OHC{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}OH
  4. DCH3CH2CH2CHOC{H}_{3}C{H}_{2}C{H}_{2}CHO

Correct answer

B. CH3CH=CHCH2OHC{H}_{3}CH = CHC{H}_{2}OH

Step-by-step solution

LiAlH4LiAl{H}_{4} convert ester into alcohol by reduction, it does not reduce π\pi bond between carbon atoms.
The major product of the following reaction is: C H _ 3 CH = CHC O _ 2 C H _ 3 LiAl H _ 4 →
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