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JEE Main 2003
Exam
JEE Main
Year
2003
Subject
Chemistry
Chapter
Carboxylic Acid Derivatives

JEE Main 2003 · Chemistry · Carboxylic Acid Derivatives

When CH_2=CH-COOH is reduced with LiAlH_4 , the compound obtained...

When CH2=CH−COOH\mathrm{CH}_2=\mathrm{CH}-\mathrm{COOH} is reduced with LiAlH4\mathrm{LiAlH}_4, the compound obtained will be

Options

  1. ACH2=CH−CH2OH\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}_2 \mathrm{OH}
  2. BCH3−CH2−CH2OH\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2 \mathrm{OH}
  3. CCH3−CH2−CHO\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CHO}
  4. DCH3−CH2−COOH\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{COOH}

Correct answer

A. CH2=CH−CH2OH\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}_2 \mathrm{OH}

Step-by-step solution

LiAlH4\mathrm{LiAl}^{\mathrm{H}}{ }_4 can reduce COOH\mathrm{COOH} group and not the double bond CH2=CH−COOH⟶LAHCH2=CH−CH2OH\mathrm{CH}_2=\mathrm{CH}-\mathrm{COOH} \underset{\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}_2 \mathrm{OH}}{\stackrel{\mathrm{LAH}}{\longrightarrow}}
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