According to Lewis theory, the total number of bond-pairs and lone pair of electrons around the central atom of XeO₆⁴⁻ ion is _____.

Step-by-step solution

The central atom in XeO₆⁴⁻ is Xenon (Xe). The number of valence electrons in Xe is 8 . Let the oxidation state of Xe in XeO₆⁴⁻ be x . x + 6(-2) = -4 x = +8 Since the oxidation state of Xe is +8 , all 8 of its valence electrons are involved in bonding with the 6 oxygen atoms. There are no non-bonding electrons left on the central atom. Number of lone pairs on Xe = 0 Xe forms 6 bonds with the 6 oxygen atoms (and 2 bonds to satisfy its +8 oxidation state and minimize formal charge). Number of bond-pairs = 6 Total numb