JEE Main 202624 JanuaryMorning Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 24 January
- Shift
- Morning Shift
- Subject
- Chemistry
- Chapter
- Chemical Bonding and Molecular Structure
JEE Main 2026 · 24 January · Morning Shift · Chemistry · Chemical Bonding and Molecular Structure
Among the following, the CORRECT combinations are A. IF_ 3 arrow ~T...
Among the following, the CORRECT combinations are
A. -shaped (sp\left.{ }^{3} \mathrm{~d}\right)\mathrm{IF}_{5} \rightarrow
C. Pentagonal bipyramidal \left(\mathrm{sp}^{3} \mathrm{~d}^{3}\right)\mathrm{ClO}_{4}{ }^{-} \rightarrow
Choose the correct answer from the options given below:
A. -shaped (sp\left.{ }^{3} \mathrm{~d}\right)\mathrm{IF}_{5} \rightarrow
C. Pentagonal bipyramidal \left(\mathrm{sp}^{3} \mathrm{~d}^{3}\right)\mathrm{ClO}_{4}{ }^{-} \rightarrow
Choose the correct answer from the options given below:
Options
- AB, C and D Only
- BA and B Only
- CA, B and C Only
- DA, B, C and D
Correct answer
C. A, B and C Only
Step-by-step solution
Analyzing geometry and hybridization:
A. IF₃: Iodine has 7 valence electrons, forms 3 bonds with F, leaving 2 lone pairs. Total electron pairs = 5 (trigonal bipyramidal geometry). Molecular shape is T-shaped. Hybridization = sp³d. CORRECT.
B. IF₅: Iodine forms 5 bonds with F and has 1 lone pair. Total electron pairs = 6 (octahedral geometry). Molecular shape is square pyramidal with 1 lone pair in axial position. Hybridization = sp³d². CORRECT.
C. IF₇: Iodine forms 7 bonds with F and has 0 lone pairs. Total electron pairs = 7. Molecular shape is pentagonal bipyramidal. Hybridization = sp³d³. CORRECT.
D. ClO₄⁻: Chlorine has 7 valence electrons + 1 from charge = 8. Bonded to 4 O atoms with 0 lone pairs. Total electron pairs = 4 (tetrahedral geometry). Molecular shape is tetrahedral, NOT square planar. Hybridization = sp³, NOT sp²d. INCORRECT.
Correct combinations: A, B, and C.
A. IF₃: Iodine has 7 valence electrons, forms 3 bonds with F, leaving 2 lone pairs. Total electron pairs = 5 (trigonal bipyramidal geometry). Molecular shape is T-shaped. Hybridization = sp³d. CORRECT.
B. IF₅: Iodine forms 5 bonds with F and has 1 lone pair. Total electron pairs = 6 (octahedral geometry). Molecular shape is square pyramidal with 1 lone pair in axial position. Hybridization = sp³d². CORRECT.
C. IF₇: Iodine forms 7 bonds with F and has 0 lone pairs. Total electron pairs = 7. Molecular shape is pentagonal bipyramidal. Hybridization = sp³d³. CORRECT.
D. ClO₄⁻: Chlorine has 7 valence electrons + 1 from charge = 8. Bonded to 4 O atoms with 0 lone pairs. Total electron pairs = 4 (tetrahedral geometry). Molecular shape is tetrahedral, NOT square planar. Hybridization = sp³, NOT sp²d. INCORRECT.
Correct combinations: A, B, and C.