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JEE Main202623 January 2026Morning ShiftChemistryChemical Bonding and Molecular StructureActual

Identify the molecule (X) with maximum number of lone pairs of electrons (obtained using Lewis dot structure) among HNO ₃, H ₂ SO ₄, NF ₃ and O ₃ . Choose the correct bond angle made by the central atom of the molecule ( X ) .

Options

  1. A116^
  2. B102^
  3. C107^
  4. D120^

Correct answer

B. 102^

Step-by-step solution

Analyzing lone pairs on central atoms: HNO₃: N is central with 3 bonds and 0 lone pairs H₂SO₄: S is central with 4 bonds and 0 lone pairs NF₃: N is central with 3 bonds and 1 lone pair O₃: Central O with 2 bonding regions and 1 lone pair NF₃ has maximum lone pairs (1) with the clearest structure. N undergoes sp³ hybridization with 1 lone pair and 3 bonding pairs giving trigonal pyramidal geometry. The F-N-F bond angle is reduced from ideal tetrahedral 109.5° due to lone pair repulsion, resulting in approximately 10

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