JEE Main 202623 JanuaryMorning Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 23 January
- Shift
- Morning Shift
- Subject
- Chemistry
- Chapter
- Chemical Bonding and Molecular Structure
JEE Main 2026 · 23 January · Morning Shift · Chemistry · Chemical Bonding and Molecular Structure
Identify the molecule (X) with maximum number of lone pairs of...
Identify the molecule with maximum number of lone pairs of electrons (obtained using Lewis dot structure) among and . Choose the correct bond angle made by the central atom of the molecule .
Options
- A
- B
- C
- D
Correct answer
B.
Step-by-step solution
Analyzing lone pairs on central atoms:
HNO₃: N is central with 3 bonds and 0 lone pairs
H₂SO₄: S is central with 4 bonds and 0 lone pairs
NF₃: N is central with 3 bonds and 1 lone pair
O₃: Central O with 2 bonding regions and 1 lone pair
NF₃ has maximum lone pairs (1) with the clearest structure. N undergoes sp³ hybridization with 1 lone pair and 3 bonding pairs giving trigonal pyramidal geometry. The F-N-F bond angle is reduced from ideal tetrahedral 109.5° due to lone pair repulsion, resulting in approximately 102°.
HNO₃: N is central with 3 bonds and 0 lone pairs
H₂SO₄: S is central with 4 bonds and 0 lone pairs
NF₃: N is central with 3 bonds and 1 lone pair
O₃: Central O with 2 bonding regions and 1 lone pair
NF₃ has maximum lone pairs (1) with the clearest structure. N undergoes sp³ hybridization with 1 lone pair and 3 bonding pairs giving trigonal pyramidal geometry. The F-N-F bond angle is reduced from ideal tetrahedral 109.5° due to lone pair repulsion, resulting in approximately 102°.