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JEE Main 202621 JanuaryEvening Shift
Exam
JEE Main
Year
2026
Date
21 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Chemical Bonding and Molecular Structure

JEE Main 2026 · 21 January · Evening Shift · Chemistry · Chemical Bonding and Molecular Structure

Given below are two statements: Statement I : The correct order in...

Given below are two statements:
Statement I : The correct order in terms of bond dissociation enthalpy is Cl2>Br2>F2>\mathrm{Cl}_{2}>\mathrm{Br}_{2}>\mathrm{F}_{2}>\mathrm{I}2_{2}.
Statement II: The correct trend in the covalent character of the metal halides is [SnCl4>SnCl2]\left[\mathrm{SnCl}_{4}>\mathrm{SnCl}_{2}\right], \left[\mathrm{PbCl}_{4}>\mathrm{PbCl}_{2}\right]and[UF4>UF6]and \left[\mathrm{UF}_{4}>\mathrm{UF}_{6}\right].
In the light of the above statements, choose the correct answer from the options given below :

Options

  1. AStatement I is false but Statement II is true
  2. BBoth Statement I and Statement II are false
  3. CStatement I is true but Statement II is false
  4. DBoth Statement I and Statement II are true

Correct answer

C. Statement I is true but Statement II is false

Step-by-step solution

Statement I: The bond dissociation enthalpy of halogens follows the order Cl2>Br2>F2>I2Cl_2 > Br_2 > F_2 > I_2. The bond energy of F2F_2 is lower than Cl2Cl_2 and Br2Br_2 due to the high inter-electronic repulsion between the lone pairs on the small fluorine atoms. Thus, Statement I is true.

Statement II: According to Fajan's rules, for a given metal, the compound with the metal in a higher oxidation state has more covalent character due to higher polarizing power. Therefore, SnCl4>SnCl2SnCl_4 > SnCl_2 and PbCl4>PbCl2PbCl_4 > PbCl_2 are correct. However, for Uranium halides, UF6UF_6 has a higher oxidation state (+6) than UF4UF_4 (+4), so UF6UF_6 is more covalent than UF4UF_4. The statement claims UF4>UF6UF_4 > UF_6, which is incorrect. Thus, Statement II is false.
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