JEE Main 2025 2 April Morning Shift
Exam JEE Main
Year 2025
Date 2 April
Shift Morning Shift
Subject Chemistry
Chapter Chemical Bonding and Molecular Structure JEE Main 2025 · 2 April · Morning Shift · Chemistry · Chemical Bonding and Molecular Structure
Among (SO_2, NF_3, NH_3, XeF_2, ClF_3) and (SF_4), the...
Among (\mathrm{SO}_2, \mathrm{NF}_3, \mathrm{NH}_3, \mathrm{XeF}_2, \mathrm{ClF}_3) and (\mathrm{SF}_4), the hybridization of the molecule with non-zero dipole moment and highest number of lone-pairs of electrons on the central atom is
Options A (\mathrm{sp}^3) B (\mathrm{dsp}^2) C (\mathrm{sp}^3 \mathrm{~d}^2) D (\mathrm{sp}^3 \mathrm{~d}) Correct answer D. (\mathrm{sp}^3 \mathrm{~d})
Step-by-step solution
(
MoleculeHybridisation < t r > D i p o l e < / t d > < / t r > < t r > < t d > < t d > M o m e n t < / t d > \begin{array}{c}<tr> Dipole</td></tr><tr><td><td> Moment </td>\end{array} < t r > D i p o l e < / t d >< / t r >< t r >< t d >< t d > M o m e n t < / t d > < t d > L o n e p a i r o n t h e < / t d > < / t r > < t r > < t d > < / t d > c e n t r a l a t o m < t d > \begin{array}{c}<td> Lone pair on the</td></tr><tr><td></td> central atom <td>\end{array} < t d > L o n e p ai ro n t h e < / t d >< / t r >< t r >< t d >< / t d > ce n t r a l a t o m < t d > sp^2 Non-zero 1 sp^3 Non-zero 1 NH_3sp^3 Non-zero 1 XeF_2 sp^3 d zero 3 sp^3 d Non-zero 2 sp^3 d Non-zero 1
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