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JEE Main 202528 JanuaryEvening Shift
Exam
JEE Main
Year
2025
Date
28 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Chemical Bonding and Molecular Structure

JEE Main 2025 · 28 January · Evening Shift · Chemistry · Chemical Bonding and Molecular Structure

Total number of molecules/species from following which will be...

Total number of molecules/species from following which will be paramagnetic is ______ O2,O2+,O2−,NO,NO2,CO,K2\mathrm{O}_2, \mathrm{O}_2^{+}, \mathrm{O}_2^{-}, \mathrm{NO}, \mathrm{NO}_2, \mathrm{CO}, \mathrm{K}_2\left[\mathrm{NiCl}_4\right],\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right] \mathrm{Cl}_3, \mathrm{~K}_2\left[\mathrm{Ni}(\mathrm{CN})_4\right]

Correct answer

0

Step-by-step solution

O2→2\mathrm{O}_2 \rightarrow 2 unpaired electrons according to MOT O2+→1\mathrm{O}_2^{+} \rightarrow 1 unpaired electrons according to MOT O2−→1\mathrm{O}_2^{-} \rightarrow 1 unpaired electrons according to MOT NO→\mathrm{NO} \rightarrow odd electron species NO2→\mathrm{NO}_2 \rightarrow odd electron species K2[NiCl4]→Ni2+⇒3 d8\mathrm{K}_2\left[\mathrm{NiCl}_4\right] \rightarrow \mathrm{Ni}^{2+} \Rightarrow 3 \mathrm{~d}^8 weak Ligand, C.N. =4=4 ⇒\Rightarrow Tetrahedral, Paramagnetic with 2 unpaired electrons
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