Total number of electrons present in ( ( ^* ) ) molecular orbitals of ( O ₂, O ₂ ⁺ ) and ( O ₂⁻ ) is _______.

Step-by-step solution

aligned & O ₂(16 e ): ( _ 1 ~s )^2 ( _ 1 ~s ^* )^2 ( _ 2 ~s )^2 ( _ 2 ~s ^* )^2 & ( _ 2 p )^2 [ ( _ 2 p )^2= ( _ 2 p )^2 ], [ ( _ 2 p ^* )^1= ( m _ 2 p ^* )^1 ] aligned Number of e ⁻ present in ( ^* ) of O ₂=2 Number of e ⁻ present in ( ^* ) of O ₂⁺=1 Number of e ⁻ present in ( ^* ) of O ₂⁻=3 So total e ⁻ in ( ^* )=2+1+3=6