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JEE Main 20249 AprilEvening Shift
Exam
JEE Main
Year
2024
Date
9 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Chemical Bonding and Molecular Structure

JEE Main 2024 · 9 April · Evening Shift · Chemistry · Chemical Bonding and Molecular Structure

Total number of electrons present in ((π^*)) molecular orbitals of...

Total number of electrons present in (\left(\pi^*\right)) molecular orbitals of (\mathrm{O}_2, \mathrm{O}_2{ }^{+}) and (\mathrm{O}_2^{-}) is _______.

Correct answer

0

Step-by-step solution

O2(16e):(σ1 s)2(σ1 s∗)2(σ2 s)2(σ2 s∗)2(σ2p)2[(π2p)2=(π2p)2],[(π2p∗)1=(m2p∗)1]\begin{aligned} & \mathrm{O}_2(16 \mathrm{e}):\left(\sigma_{1 \mathrm{~s}}\right)^2\left(\sigma_{1 \mathrm{~s}}^*\right)^2\left(\sigma_{2 \mathrm{~s}}\right)^2\left(\sigma_{2 \mathrm{~s}}^*\right)^2 \\ & \left(\sigma_{2 \mathrm{p}}\right)^2\left[\left(\pi_{2 \mathrm{p}}\right)^2=\left(\pi_{2 \mathrm{p}}\right)^2\right],\left[\left(\pi_{2 \mathrm{p}}^*\right)^1=\left(\mathrm{m}_{2 \mathrm{p}}^*\right)^1\right] \end{aligned}
Number of e−\mathrm{e}^{-}present in \left(\pi^*\right) of \mathrm{O}_2=2NumberofNumber of\mathrm{e}^{-}presentin(π∗)ofO2+=1present in \left(\pi^*\right) of \mathrm{O}_2^{+}=1 Number of e−\mathrm{e}^{-}present in \left(\pi^*\right) of \mathrm{O}_2^{-}=3SototalSo total\mathrm{e}^{-}in(π∗)=2+1+3=6in \left(\pi^*\right)=2+1+3=6
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